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jQuery獲取某天的農(nóng)歷日期并判斷是否除夕或新年的方法
來源:易賢網(wǎng) 閱讀:1822 次 日期:2016-08-04 15:31:12
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本文實(shí)例講述了jQuery獲取某天的農(nóng)歷日期并判斷是否除夕或新年的方法。分享給大家供大家參考,具體如下:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"

"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml">

<head>

<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />

<script src="jquery.min.js" type="text/javascript"></script>

<script type="text/javascript">

  //------------------- Begin ----------------------

  CalendarHelper={};

  CalendarHelper.GetCNDate = function (D) {

    var CalendarData = new Array(100);

    var madd = new Array(12);

    var tgString = "甲乙丙丁戊己庚辛壬癸";

    var dzString = "子丑寅卯辰巳午未申酉戌亥";

    var numString = "一二三四五六七八九十";

    var monString = "正二三四五六七八九十冬臘";

    var weekString = "日一二三四五六";

    var sx = "鼠?;⑼谬埳唏R羊猴雞狗豬";

    var cYear, cMonth, cDay, TheDate;

    CalendarData = new Array(0xA4B, 0x5164B, 0x6A5, 0x6D4, 0x415B5, 0x2B6, 0x957, 0x2092F, 0x497, 0x60C96, 0xD4A, 0xEA5, 0x50DA9, 0x5AD, 0x2B6, 0x3126E, 0x92E, 0x7192D, 0xC95, 0xD4A, 0x61B4A, 0xB55, 0x56A, 0x4155B, 0x25D, 0x92D, 0x2192B, 0xA95, 0x71695, 0x6CA, 0xB55, 0x50AB5, 0x4DA, 0xA5B, 0x30A57, 0x52B, 0x8152A, 0xE95, 0x6AA, 0x615AA, 0xAB5, 0x4B6, 0x414AE, 0xA57, 0x526, 0x31D26, 0xD95, 0x70B55, 0x56A, 0x96D, 0x5095D, 0x4AD, 0xA4D, 0x41A4D, 0xD25, 0x81AA5, 0xB54, 0xB6A, 0x612DA, 0x95B, 0x49B, 0x41497, 0xA4B, 0xA164B, 0x6A5, 0x6D4, 0x615B4, 0xAB6, 0x957, 0x5092F, 0x497, 0x64B, 0x30D4A, 0xEA5, 0x80D65, 0x5AC, 0xAB6, 0x5126D, 0x92E, 0xC96, 0x41A95, 0xD4A, 0xDA5, 0x20B55, 0x56A, 0x7155B, 0x25D, 0x92D, 0x5192B, 0xA95, 0xB4A, 0x416AA, 0xAD5, 0x90AB5, 0x4BA, 0xA5B, 0x60A57, 0x52B, 0xA93, 0x40E95);

    madd[0] = 0;

    madd[1] = 31;

    madd[2] = 59;

    madd[3] = 90;

    madd[4] = 120;

    madd[5] = 151;

    madd[6] = 181;

    madd[7] = 212;

    madd[8] = 243;

    madd[9] = 273;

    madd[10] = 304;

    madd[11] = 334;

    function GetBit(m, n) {

      return (m >> n) & 1;

    }

    function e2c() {

      TheDate = (arguments.length != 3) ? new Date() : new Date(arguments[0], arguments[1], arguments[2]);

      var total, m, n, k;

      var isEnd = false;

      var tmp = TheDate.getYear();

      if (tmp < 1900) {

        tmp += 1900;

      }

      total = (tmp - 1921) * 365 + Math.floor((tmp - 1921) / 4) + madd[TheDate.getMonth()] + TheDate.getDate() - 38;

      if (TheDate.getYear() % 4 == 0 && TheDate.getMonth() > 1) {

        total++;

      }

      for (m = 0; ; m++) {

        k = (CalendarData[m] < 0xfff) ? 11 : 12;

        for (n = k; n >= 0; n--) {

          if (total <= 29 + GetBit(CalendarData[m], n)) {

            isEnd = true; break;

          }

          total = total - 29 - GetBit(CalendarData[m], n);

        }

        if (isEnd) break;

      }

      cYear = 1921 + m;

      cMonth = k - n + 1;

      cDay = total;

      if (k == 12) {

        if (cMonth == Math.floor(CalendarData[m] / 0x10000) + 1) {

          cMonth = 1 - cMonth;

        }

        if (cMonth > Math.floor(CalendarData[m] / 0x10000) + 1) {

          cMonth--;

        }

      }

    }

    function GetcDateString() {

      var tmp = "";

      tmp += tgString.charAt((cYear - 4) % 10);

      tmp += dzString.charAt((cYear - 4) % 12);

      tmp += "(";

      tmp += sx.charAt((cYear - 4) % 12);

      tmp += ")年 ";

      if (cMonth < 1) {

        tmp += "(閏)";

        tmp += monString.charAt(-cMonth - 1);

      } else {

        tmp += monString.charAt(cMonth - 1);

      }

      tmp += "月";

      tmp += (cDay < 11) ? "初" : ((cDay < 20) ? "十" : ((cDay < 30) ? "廿" : "三十"));

      if (cDay % 10 != 0 || cDay == 10) {

        tmp += numString.charAt((cDay - 1) % 10);

      }

      return tmp;

    }

    function GetLunarDay(solarYear, solarMonth, solarDay) {

      //solarYear = solarYear<1900?(1900+solarYear):solarYear;

      if (solarYear < 1921 || solarYear > 2020) {

        return "";

      } else {

        solarMonth = (parseInt(solarMonth) > 0) ? (solarMonth - 1) : 11;

        e2c(solarYear, solarMonth, solarDay);

        return GetcDateString();

      }

    }

    var yy = D.getFullYear();

    var mm = D.getMonth() + 1;

    var dd = D.getDate();

    var ww = D.getDay();

    var ss = parseInt(D.getTime() / 1000);

    if (yy < 100) yy = "19" + yy;

    return GetLunarDay(yy, mm, dd);

  };

  CalendarHelper.GetAddDay = function (D, v) {

    var LSTR_ndate = D;

    var LSTR_Year = LSTR_ndate.getYear();

    var LSTR_Month = LSTR_ndate.getMonth();

    var LSTR_Date = LSTR_ndate.getDate();

    //處理

    var uom = new Date(LSTR_Year, LSTR_Month, LSTR_Date);

    uom.setDate(uom.getDate() + v); //取得系統(tǒng)時(shí)間的前一天,重點(diǎn)在這里,負(fù)數(shù)是前幾天,正數(shù)是后幾天

    return uom;

  }

  //是否除夕

  CalendarHelper.IsLastDayBeforeNewYearOfCN = function (D) {

    var strCurrDay = CalendarHelper.GetCNDate(D);

    var strNextDay = CalendarHelper.GetCNDate(CalendarHelper.GetAddDay(D, 1));

    //alert(strCurrDay+","+strNextDay);

    return strCurrDay.split('年')[0] != strNextDay.split('年')[0];

  };

  //是否春節(jié)

  CalendarHelper.IsNewYearOfCN = function (D) {

    var strCurrDay = CalendarHelper.GetCNDate(D);

    var strPrevDay = CalendarHelper.GetCNDate(CalendarHelper.GetAddDay(D, -1));

    //alert(strCurrDay+","+strPrevDay);

    return strCurrDay.split('年')[0] != strPrevDay.split('年')[0];

  };

  //------------------- End ----------------------

  var d1 = new Date();

  var d2 = new Date(2013, 1, 9); //注:此處相當(dāng)于2013年2月9號(hào)

  var d3 = new Date(2013, 1, 10);

  var result = GetResult(d1) + GetResult(d2) + GetResult(d3);

  alert(result);

  function GetResult(D) {

    var y = D.getFullYear();

    var m = D.getMonth() + 1;

    var dd = D.getDate();

    var str = y + "年" + m + "月" + dd + "日";

    var isR = CalendarHelper.IsLastDayBeforeNewYearOfCN(D);

    var isN = CalendarHelper.IsNewYearOfCN(D);

    return "日期:"+str+","+ (isR?"是":"不是") + "除夕" + "," + (isN?"是":"不是") + "春節(jié)\n\n" ;

  }

</script>

</head>

<body>

</body>

</html>

希望本文所述對(duì)大家jQuery程序設(shè)計(jì)有所幫助。

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